Four matches were played in the five-match Test series between India and England. Now, the fifth and final match of the series will be played at the Himachal Pradesh Cricket Association Stadium in Dharamshala from Thursday, March 7. This game will be very important for Indian spinner Ravichandran Ashwin and England batsman Jonny Bairstow. In this Dharamshala Test, both players will complete a special ‘century’.
In fact, the Indian spinner and the England batsman will take the field for the 100th Test as part of the Dharamshala Test. Ashwin and Bairstow have played 99 Tests so far. In such a situation, both players complete their century test.
Both players have played the last four games of the series so far. However, Bairstow’s form was not good. But then again, Ashwin has performed amazingly. In such a situation, it is almost certain that Ashwin will clear the Dharamshala test. However, England definitely want to give Bairstow the chance to play his 100th Test.
After four matches of the India-England series, Ravichandran Ashwin has taken 17 wickets at an average of 30.41. He ranks second overall when it comes to most wickets in the series. Furthermore, he also contributed with the bat in all four Tests.
Jonny Bairstow, who has been struggling with poor form against India, has scored just 170 runs in 8 innings from 4 games at an average of 21.25.
The Indian spinner made his Test debut against West Indies in November 2011. So far, Ashwin has played 99 red-ball matches, bowled 187 innings and taken 507 wickets at an average of 23.91. Apart from this, he has scored 3309 runs in 140 innings at an average of 26.47.
The English batsman has scored 5974 runs at an average of 36.42 in the 99 Tests played so far. During this period he composed 12 centuries and 26 half centuries. We tell you that Bairstow made his Test debut against West Indies in May 2012.