The first match of the five-match T20 series between India and Pakistan ended in a very interesting way. Team India, chasing the big target of 209 runs, had to score just two runs in four balls at a time, but here three wickets fell in a row and the game stalled. Now India needed a run off the last ball. Rinku Singh was ahead and scored a wonderful six off Shaun Abbott’s ball. Here the umpire gave a signal and then cricket fans got the chance to deal with an interesting rule.
Even after the umpire’s signal, Team India’s victory was assured but Rinku Singh’s six was wasted. This happened because Shaun Abbott’s ball turned out to be a no-ball. Although in cricket a six is counted even in a no-ball, why was Rinku Singh’s last six not counted? The answer to this question continued to confuse cricket fans. Here we give a simple answer to this question.
In fact, when Rinku Singh hit a six on the last ball of the game, the Indian team only needed one run to win. Since Shaun Abbott’s ball was a no-ball, India had an extra run before the delivery. This means the Indian team won. In such a situation the six had no meaning. For this reason, the last ball and the last shot of this game were rejected. Yes, if India needed two runs to win here, then Rinku Singh’s sixth run would definitely have counted this match.
In this game, Australia posted a huge score of 208 runs thanks to Jose Inglis’ innings of 110 runs off 50 balls. In response, India reached the target with one ball to spare thanks to Suryakumar Yadav’s explosive innings of 82 runs in 40 balls. Here too, Ishan Kishan played an important innings of 58 runs in 39 balls.
